An object starts from rest and undergoes uniform acceleration. during the first second it travels 5.0 meters. how far does it travel during the third second

  Distance traveled in third second = 25 meter.

Explanation:

  We have equation of motion, , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 During the first second it travels 5.0 meters

  In this case u = 0 m/s, t = 1 second and s = 5 meters

  Substituting

  Now we need to find how much distance it travel during third second.

        Distance traveled in third second = Distance covered in 3 seconds - Distance covered in 2 seconds

      Distance covered in 3 seconds =

      Distance covered in 2 seconds =

 Distance traveled in third second = 45 - 20 = 25 meter

they should be similar or the same