In this lab, you will use a dynamics track to generate collisions between two carts. if momentum is conserved, what variable change would result in a velocity change after a collision? in the space below, write a scientific question that you will answer by doing this experiment. answer for e2020: how does changing mass affect colliding objects?

The scientific question that needs to be answered by doing the experiment where a dynamic track generates collisions between two carts is;

How does changing mass affect colliding objects?

        In collisions whether elastic collision or inelastic collision, momentum is always conserved.

Now, we want to know the variable change that would result in a velocity change after collision.

         We know from newton's first law of motion that an object will continue in its' present state of rest or in constant motion unless it is acted upon by an external force.

Now, this means that the speed will increase the more a force is applied to an object. We know that an increase in mass means an increase in force from the formula F = ma.

        Now, momentum is the product of mass and velocity. Thus, we would like to know the impact of changing mass on the velocity because when the mass of two colliding objects is increased, their final velocity will decrease since momentum is conserved.

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Here by momentum conservation we can write

so here from above equation we can say the final speed after collision depends upon the mass of two objects

here if we change the mass of two colliding object then the final speed will change

for example

If we take two objects of same masses then after collision the speed of two objects will interchange

While if the two colliding object are such that one of the object is very heavy then after collision there is no effect on its velocity.

So if mass is changed then the speed of the object after collision will change

the speed of object after collision is given by

So by above equations we can show the dependency of two speed on mass

b

explanation:

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz