State the kinematic quantity that is equivalent to the slope of a position-time graph

The figure shows the arrangement of given data.

The displacement is considered along X direction and time along Y direction.

The slope of the graph is given by tan θ

So tan θ = Δx/Δt = Velocity between those two points considered for finding slope of graph.

So slope of position time is graph is equivalent to kinematic quantity Velocity.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2