Agolfer rides in a golf cart at an average speed of 3.10 m/s for 23.0 s. she then gets out of the cart and starts walking at an average speed of 1.20 m/s. for how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 2.60 m/s

Answer;

= 10.4 sec

Explanation and solution;

Average velocity = Total distance traveled/Total time

Total distance traveled = 3.1 * 29 + 1.2(T) = 89.9 + 1.2T

where  

T = walking time of golfer  

Total time = 29 + T

and substituting appropriately into Equation 1  

2.6 = (89.9 + 1.2T)/(29 + T)  

Simplifying the above,  

2.6(29 + T) = 89.9 + 1.2T

75.4 + 2.6T = 89.9 + 1.2T  

1.4T = 14.5  

T = 10.4 sec.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

where is the photo and the answer choices?