The concentration of carbon monoxide in an urban apartment is 48μg/m3. what mass of carbon monoxide in grams is present in a room measuring 10.6ft×14.8ft×20.5ft?

m = g

Explanation:

Volume = 10.6 × 14.8 × 20.5 ft = 3216.04 ft³

1 feet³ = 0.0283168 meter ³

Now convert feet³ to meter³

Volume =   3216.04 ft³ × (3.048/1 m³/ft³)  = 91.06811131 m³

This question gives the density as 48μg/m3

μ =

The formula for density is

Solve for m

m = g

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