Aparticle moves along a circular path over a horizontal xy coordinate system, at constant speed. at time t1 = 5 s, it is at point (4.00 m, 3.00 m) with velocity (1.50 m/s)j and acceleration in the positive x direction. at time t2 = 10 s, it has velocity (-1.5 m/s)i hat and acceleration in the positive y direction. what are the coordinates of the center of the circular path?

Initial velocity at t = 5 s

final velocity at t = 10 s

so the time taken by the object to revolve by 270 degree is t = 10 - 5 = 5s

so here we can find the angular speed

now we know that

so the coordinates of the center will be

so the coordinates of center is (5.6 m,3 m)

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by