Oil has a density ρ of 860kg/m3. an oil droplet is suspended between two plates 1.0cm apart by adjusting the potential difference between them to 1177v. when the voltage is removed, the droplet falls and quickly reaches constant speed. it is timed with a stopwatch and falls 3.00mm in 7.33s. the viscosity of air is 1.83×10−5kg/m⋅s. what is the droplet's charge q?

After reaching the terminal velocity the speed of the oil drop is given as

it drop by 3 mm in 7.33 s

now by the formula of terminal speed

so the radius of drop is 0.16 mm

Now the electric field between the plates is given as

now we will use the condition of equilibrium

so above is the charge on the drop

where is the photo and the answer choices?

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.