An iron block of mass 18 kg is heated from 285 k to 318 k. if 267.3 kj is required, what is the specific heat of iron

q = mcΔT

where, q = heat required in Joules

m = mass in grams

c = specific heat in joules/gram °C

ΔT = change in temperature = Final temperature(T₂)-Initial Temperature (T₁)

Given, q=267.3 kJ=267300 Joules

m=18kg=18000 gram

ΔT=318-285= 33K = 33°C

Rearranging formula, c=

c=

c=0.45 joules/gram °C

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests