The acceleration due to gravity is g at the earth's surface. an earth satellite is orbiting at a distance from the earth's surface equal to one earth radius. at this location, what is the acceleration due to gravity

The acceleration due to gravity is g/4

The acceleration above the earth surface is given by the relation

g^'=gr^2/〖(h+r)〗^2

Since the satellite orbits the earth in a orbit of radius equal to earth radius, therefore

g^'=(gr^2)/〖(r+r)〗^2 =g/4

Thus the acceleration due to gravity on the satellite is g/4.

answer: option c.

explanation: