Questions from chapter 8.rotational of a rigid body

the moment of inertia of wheel= 1/2mr²

m= mass of wheel= 2.8 kg

r= radius

i= 1/2 (2.8)(0.35)²=0.1715 kgm²

(a) torque = F r

F= force=5 N

r= radius=0.35 m

τ= 5 (0.35)

τ= 1.75 Nm

(b) for angular acceleration, we use

τ= iα

τ= torque= 1.75 Nm

i= moment of inertia=0.1715 kgm²

so 1.75 =0.1715 α

α=10.2 rad/s²

(c) for angular displacement θ, we use the kinematic equation,

θ= ωo t + 1/2α t²

ωo= initial angular velocity=0

t= time=4 s

α= angular acceleration=10.2 rad/s²

so θ = 0 (4) + 1/2 (10.2)(4)²

θ=81.6 rad

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.