A1.0-mm-diameter ball bearing has 2.0 * 109 excess electrons. what is the ball bearing's potential?

Bearing potential of Ball= 5760 V

Explanation:

the electric potential is given by

Q= electrostatic constant= 9 x 10⁹ Nm²/C

Q= charge= n e

n= number of electrons= 2 x 10⁹

e= charge of electron=-1.6 x 10⁻¹⁹ C

so Q=2 x 10⁹ (-1.6 x 10⁻¹⁹ )

Q= -3. 2 x 10⁻¹⁰ C

r= radius of sphere=1/2 mm= 0.0005 m

V= 5760 volt

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

c)as speed changes, wavelength and frequency change.

everything changes!