Eric has just had a sandwich that contained the equivalent of 1.80 mol of glucose the standard molar entropy of reaction is 182 j k-1 mol-1. how much energy (in kj) is available for sustaining eric's muscular and nervous activity assuming a body temperature of 36.9oc

Energy available for sustaining Eric's muscular and nervous activity can be calculated by,

Energy available= Standard molar entropy×Number of moles×Temperature

We have, standard molar entropy of glucose = 182 J/K mol

Number of moles of glucose = 1.80 mol

Body temperature = 36.9° C = 36.9 + 273.15 = 310.05 K

Substituting the value we get,

Energy available = 182×1.80×310.05 = 100,456.2 J

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s