Achild is sitting on the outer edge of a merry-go-round that is 18 m in diameter. if the merry-go-round makes 5.9 rev/min, what is the velocity of the child in m/s?

The velocity of the kid is 5.6 m/s

Explanation: Ok, the velocity of the kid will be:

v = w*r

where r is the radius, and w is the frequency.

We know that the diameter is 18m, and the diameter is equal to two times the radius. So r = 18m/2 = 9m

Now, we know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length, if the kid does 5.9 revolutions in one minute, then the kid spins at v = 5.9*2pi*9m/min

But we want to write this in meters per second, this means that we need to divide it by 60.

v = (5.9*2pi*9/60)m/s = 5.56 m/s

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

did yall get answers for this yet