A3.0-ω resistor is connected in parallel with a 6.0-ω resistor. this combination is then connected in series with a 4.0-ω resistor. the resistors are connected across an ideal 12-volt battery. how much power is dissipated in the 3.0-ω resistor? a 3.0-ω resistor is connected in parallel with a 6.0-ω resistor. this combination is then connected in series with a 4.0-ω resistor. the resistors are connected across an ideal 12-volt battery. how much power is dissipated in the 3.0-ω resistor? 12 w 2.7 w 6.0 w 5.3 w

first of all a 3 ohm resistance is connected in parallel with 6 ohm resistance so we will have

now it is connected in series with 4 ohm resistance

So we will have net resistance given by

Now this combination of 6 ohm resistance is connected across a battery of 12 V

so now we will have total current in the circuit calculated by ohm's law

now this 2 A current will divide in 3 ohm and 6 ohm resistance in the ratio of 2:1

so current in 3 ohm resistance is given by

now power dissipated in 3 ohm resistance is given by

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