A9-volt battery is connected to a capacitor that stores 4.5 × 10–3 joules of energy. calculate the amount of charge on the capacitor.

Amount of charge on the capacitor=q=10⁻³C

Energy stored=4.5x10⁻³ J

potential difference= 9 V

Energy stored= E= 1/2 q V

4.5x10⁻³ =1/2 q (9)

q=10⁻³C

Thus the amount of charge on the capacitor=q=10⁻³C

D. 1 × 10–3 C

Explanation:

I just took it

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