Acompressed spring has 16.2 j of elastic potential energy when it is compressed 0.30 m. what is the spring constant of the spring? 90 n/m 108 n/m 180 n/m 360 n/m

360 N/m

Explanation:

The elastic potential energy of a spring is given by

where

k is the spring constant

x is the compression/stretching of the spring

In this problem, we know the elastic potential energy, E=16.2 J, and the compression, x=0.30 m. Therefore, we can re-arrange the formula to calculate the spring constant k:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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