Particle q1 has a positive 6 µc charge. particle q2 has a positive 2 µc charge. they are located 0.1 meters apart. recall that k = 8.99 × 109 n•. what is the force applied between q1 and q2? in which direction does particle q2 want to go?

(1) The force between the two charges is 10.788 N.

(2) The direction of the particle 2 will be in opposite direction to particle 1 because both charges are positive and similar charges repel.

The given parameters:

The force between the two charges is calculated as follows;

The direction of the particle 2 will be in opposite direction to particle 1 because both charges are positive and similar charges repel.

Learn more about Coulomb's force here: link

(a) Force between the two charges

The electrostatic force between the two charges is given by:

where k is the Coulomb's constant, q1 and q2 the two charges, r their separation.

In this problem:

Substituting into the equation, we find

(b) direction of particle q2

Particle q2 wants to move in the direction of the force acting on it. The direction of the force depends on the relative sign of the two charges: like charges attract each other, opposite charges repel each other. In this case, the two charges are both positive, so they repel each other and q2 tends to move away from particle q1.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j