Suppose you are holding a container of gas, and the container has a fixed volume (i. e. it won't stretch or give to allow for expansion or contraction). if the gas pressure in the container has doubled while you were holding it, then what must have happened to the temperature?

if the pressure in the container is doubled, then the temperature will double too.

Justification:

You can rely on Gay-Lussac's law for ideal gases to answer the question.

According to that law, the pressure and temperature of a fixed amount of gas in a closed rigid container (constant volume) varie in direct proportion.

Mathematically, you can write in this way:

P/T = k

P₁ / T₁ = P₂ / T₂

That means, that if the pressure in the container is doubled, then the temperature will double too.

You can see that mathematically:

P₂ = 2 P₁

T₂ = (T₁ / P₁)(P₂) = (T₁ / P₁) (2 P₁) = 2 T₁

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

mass and volume are the answers you are looking for