Apoint charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram. what is the magnitude of the magnetic force acting on the charge? 6.6 × 10–3 n 4.9 × 10–3 n 4.9 × 103 n 6.6 × 103 n

Explanation:

The magnitude of the magnetic force acting on the charge is given by

where

is the magnitude of the charge

is the velocity of the charge

is the magnitude of the magnetic field

is the angle between the directions of v and B

Substituting the numbers into the equation, we find:

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.