Aspeedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. it began the trip at a speed of 0 m/s. by the time it reached the buoy, it was going 10 m/s. what was the average velocity of the boat? -3.33 m/s2 -1.11 m/s +1.11 m/s +3.33 m/s

Distance=20m
time=18s
Initial velocity=0m/s
Final velocity=10m/s

The equation we use to find average velocity is v=d/t (average velocity=distance/time)

V=20m/18s
V (average velocity)=1.11m/s

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

The independent variable would be the fertilizer as it is what the dependent variable (the growth of grass) depends on.