80pts what is the magnitude and direction of the electric field 4.52 to the left of a 8.15 c negative charge? plz show work

A) The magnitude of the electric field generated by a single point charge is given by

where k is the Coulomb's constant, q is the charge and r is the distance at which we calculate the field.
Since we want to know the intensity of the field at distance of r=4.52 m from the charge of q=8.15 C, the intensity of the electric field is


b) Direction of the field
The charge that produces the field is negative, and we know that the electric field generated by a negative charge points toward the charge. Therefore, the direction of the electric field is towards the charge.

"induction" is the process of charging an object without touching it.hope my answer has you : )

Hello,your answer would be iron! plz mark me brainliest! hope this !