An object is 10 cm from thé mirror, its height is 1 cm and thé focal length is 5 cm. what is thé distance from thé mirror? s1= __cm and what is the image height? h1= . an object is 10 cm from the mirror it’s height is 3 cm and thé focal length is 2 cm. what is the distance from the image t the mirror? s1= . an object is 10 cm from the mirror, its height is 3 cm and thé focal length is 2.0 cm. what is the image height? (indicate the object orientation by including the + or - sign with answer. h1= .

Note: I assume the mirror is concave, so that its focal length is positive (it is not specified in the text)

1a) We can use the mirror equation to find the distance of the image from the mirror:

where 
is the focal length
is the distance of the object from the mirror
is the distance of the image from the mirror.

Rearranging the equation, we find

so, the distance of the image from the mirror is .

1b) The image height is given by the magnification equation:

where  is the heigth of the image and  is the height of the object. By rearranging the equation and using p and q, we find

and the negative sign means the image is inverted.

2) As before, we can find the distance of the image from the mirror by using the mirror equation:

Rearranging it, we find

so, the distance of the image from the mirror is


3) As before, we find the distance of the image from the mirror by using the mirror equation:

Rearranging it, we find

so, the distance of the image from the mirror is


And now we can use the magnification equation to find the image height:

Rearranging it, we find

and the negative sign means the image is inverted.

The correct answer is  "c".  it is "c" because melting is an endothermic change, and endothermic get's energy from surroundings.