Acharge q of 1.3 × 10-16 coulombs moves from point a to a lower potential at point b in an electric field of 3.2 × 102 newtons/coulomb. if the distance traveled is parallel to the field is 1.1 × 10-2 meters, what is the difference in the potential energy? 1.22 × 10-15 joules -2.4 × 10-15 joules -3.2 × 10-15 joules -4.6 × 10-16 joules 5.6 × 10-15 joules

Difference in potential energy is,

Explanation:

It is given that,

Charge,

It moves from potential A to a lower potential B

Electric field,

Distance travelled,

We have to find the difference in potential energy. We know that the work done is stored in the form of potential energy.

Also,

is potential energy

And

So,    

Hence, the difference in potential energy is "-4.6 × 10⁻¹⁶ J"                                                           

no. dot product   =0 when vecs at right angles

elctricity and magnet is conversion to it