The force between to objects of charge +2q and -2q, respectively, is measured as -4f. if the charge on the first object is doubled and the distance between the objects is doubled, what will the force between the objects become?

Given two stationary charged point particles -as in your problem-, the force they feel is expressed by Coulomb's Law, written as:



In which  is the charge of one of the particles,  is the charge of the other particle,  is the distance between the particles, and  is simply a constant.

From Coulomb's Law, lets assume  and  are doubled, what happens to ?

→


So, the force is halved when you double the charge of one particle and the distance.
The answer is -2.

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At maximum height, kinetic energy is converted in potential energy  formula: at max height, ke = ½ * 0.27kg * (16m/s) ² = 34.56 j  so the remaining pe = (41.70 – 34.56)= 7.14 j = 0.27 kg * 9.8m/s² * h  = (9.8/7.14 * 0.27)so max height h = 5.08 or 5 m