Dave and sandy hartranft are frequent flyers with a particular airline. they often fly from city a to city b, a distance of 732732 miles. on one particular trip, they fly into the wind, and the flight takes 22 hours. the return trip, with the wind behind them, only takes 1 and one half1 1 2 hours. if the wind speed is the same on each trip, find the speed of the wind and find the speed of the plane in still air

Let the speed of the plane in still air = x
and speed of wind = y
Now from city A to B
dIstance = speed  × time
732732 = (x - y) × 2 (1)
From city B to A
Distance = speed × time
732732 = (x + y) × 1.5 (2)
From (1) and (2)
2x - 2y = 1.5x + 1.5y
0.5x = 3.5y
x = 7y
If we plug in (1)
732732 = (7y - y) × 2
732732/12 = 12y/12
y = 61061
 Since x = 7y
= 427427 miles/hr
Speed of still air plane is 427427 miles/hr
Speed of wind = 61061miles/hr