Acup on a table is pushed horizontally with a force of 0.7n. the cup remains at rest. what are all the forces that make up the net force on the cup, and what is the net force on the cup, in newtons

1) The following is the list of forces acting on the cup:
- the weight of the cup (mg), acting downward
- the normal reaction of the table (N), acting upward, that balances the weight of the cup
- the horizontal force of 0.7 N that pushes the cup
- the frictional force (), acting horizontally but in the opposite direction of the previous force, that prevents the cup from sliding

2) The net force acting on the cup is 0 N. In fact, the cup is at rest, so its acceleration is zero: for Newton's second law, if an object is not accelerating, it means the net force acting on it is zero:

where the term on the left is the resultant of the forces acting on the object, m is its mass and a its acceleration. Since the acceleration a is zero, the term on the left must be zero as well.

It should be d if not then c