Abucket contains 50 lottery balls numbered 1-50.one is drawn at random. find p(multiple of 6/2-digit number)

This is a problem of conditional probability that can be calculated by the formula:
P(B | A) = P(A ∩ B) / P(A)

We know that:
- between 1 and 50 there are 41 two-digit numbers, therefore 
P(A) = 41/50 = 0.82

- between 1 and 50 there are 8 multiples of six, therefore
P(B) = 8/50 = 0.16

- between 1 and 50 there are 7 two-digits mutiples of six, therefore
P(A ∩ B) = 7/50 = 0.14

Now, we can calculate:
P(B | A) = P(A ∩ B) / P(A)
             = 0.14 / 0.82
             = 0.17

Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%.

2,4,5,8,10 are divisible by 40