How do you find zeros when given a quadratic relation in vertex form

In order to find the zeros in a quadratic in vertex form, you need to follow a number of steps. They have been outlined for you along with a sample problem.

y = (x - 2)^2 - 16

After getting the original form, you can place a 0 in for y. In is where the graph will cross the x-axis, so it is where you will find both of your zeros.

0 = (x - 2)^2 - 16

Now take the constant and add it to both sides. In this equation, -16 is your constant. So, we'll add 16 to both sides to begin to solve.

16= (x - 2)^2

Now we can take the square root of both sides. After we do so, we take both the positive and negative version of what we get. This is because both 4 and -4 squared is equal to 16.

+/-4 = x - 2

Now we add 2 to both sides to get us what is left of x.

2 +/- 4 = x

Now that we have a final form such as this, we can separate and get two answers for our two zeros.

2 + 4 = 6

2 - 4 = -2

y=mx+b is the final answer!   : )

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.