Mathematics, 21.07.2019 08:30, maleah12x
Me problem: the standard form of a circle is (x-h)2+(y-k)2=r2 and for the parabola, y-k=a(x-h)2. the (h, k) pair will be the center of the circle and the vertex of the parabola. the radius of the circle is ‘r’ and the focal length of the parabola is f=1/(4a). for the following general conic equation: x2+y2-4x-6y-12=0 complete the following problems showing all your work: complete the square showing all your work to convert to standard form: if this is a circle, state the coordinates of the center and give the radius. if this is a parabola, state the coordinates of the vertex and give the focal length. show all your work. sketch the conic. label the values you found in part b. be sure to draw or show the radius or focal length.
Answers: 1
Mathematics, 22.06.2019 01:00, autumnrose02
Anew landowner is interested in constructing a fence around the perimeter of her property. her property is 1,080√30 feet wide and 500√20 feet long. what is the perimeter of the property? (recall that the perimeter is the sum of each side of a shape or boundary). a 1,580√40 feet b. 5,320√5 feet c. 3,160√20 feet d. 10,640√5 feet
Answers: 3
Mathematics, 22.06.2019 02:30, homeschool0123
Solve the compound inequality. graph your solution. 2x – 2 < –12 or 2x + 3 > 7 x < –5 or x > 5 x < –5 or x > 2 x < –12 or x > 2 x < –7 or x > 5
Answers: 2
Me problem: the standard form of a circle is (x-h)2+(y-k)2=r2 and for the parabola, y-k=a(x-h)2. t...
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