Given: cdkm is a parallelogram, da ⊥ ck , dk – cd = 7 ca = 6, ak = 15 find: cd and dk

In the parallelogram CDKM the value of the line segment CD and DK is 10 units and 17 units.

Pythagoras theorem says that in a right angle triangle the square of hypotenuse side is equal to the sum of square of other two legs of right angle triangle.

The quadrilateral CDKM is a parallelogram. In this parallelogram, the side DA is perpendicular to the side CK.

The difference of the side DK and CD is,

The length of the line segment CA and AK is 6 units and 15 units respectively.Then by the Pythagoras theorem,

             ....1

Again by using the Pythagoras theorem

Put the value of (AD)², from equation 1 in the above equation as,

Put the value of DK in the above equation as,

Hence, the value of DK is,

Hence, In the parallelogram CDKM the value of the line segment CD and DK is 10 units and 17 units.

Learn more about the Pythagoras theorem here;

link

it should be a and d. lmk if i'm wrong xd