Find a polynomial with integer coefficients that satisfies the given conditions degree 3 with roots 9 2 and 0

The answer to this question is y = x^3 - 11x^2 + 18x. This polynomial has a degree of 3 with roots of 9, 2, and 0.
We first make x(x-2)(x-9) and then we expand it.

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*