2^2-3/4d+1/8=0. what's the answer and steps to this equation

I see "2^2-3/4d+1/8=0."  I think you meant "2x^2-(3/4)d+(1/8)=0."  If this is correct, then simplify

2x^2-(3/4)d+(1/8)=0 by mult. every term by the LCD, which is 8:

16d2 - 6d + 1 = 0

Using the quadratic formula, I obtained:

        6 plus or minus sqrt(6^2 - 4(16)(1) )
d =
                    2(2)

Before you do anything else, ensure that you have copied down this problem completely and correctly.  Was that 2^2 or was it 2d^2? ???