Find the area of δaob 3√3 un2 4.5√3 un2 9√3 un2

The area of the ΔAOB is .

Step-by-step explanation:

As given the figure

OA = OB = 6 unit

(Radius of the circle.)

In ΔAOB

As the two sides of a triangle thus there opposite angles are also equal .

∠A = ∠B

Let us assume that ∠A = ∠B = x°

∠A + ∠O + ∠B = 180°

(By using the angle sum property of a triangle.)

∠O = 60°

x° + 60° + x° = 180°

2x = 180 - 60

2x = 120

x = 60

∠A = ∠B = 60°

Thus

∠A = ∠B = ∠O = 60°

As all the angles of the ΔAOB are 60° thus ΔAOB is a equilateral triangle .

Also all the sides of the ΔAOB are also equal i.e AB = OA = OB = 6 unit .

Formula

Where a is the side of the equilateral triangle .

a = 6 unit

Put in the above formula

6² = 36

Therefore the area of the ΔAOB is .

9√3 un2

Step-by-step explanation:

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