Answers: 2
![y= 4 x^{3} \\ \\ \frac{y}{4} = x^{3} \\ \\ \sqrt[3]{\frac{y}{4}} =x \\ \\ f^{-1}(y)= \sqrt[3]{\frac{y}{4}} \\ \\ f^{-1}(x)= \sqrt[3]{\frac{x}{4}} \\ \\ y^{-1}= \sqrt[3]{\frac{x}{4}}](/tpl/images/0116/8905/9836e.png)
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