Jane and anne are at a garage sale, and they are both buying clocks for their collections. when they leave, jane has twice as many clocks as anne does. then jane picks up 4 more at another sale on the way home. so she has 10 all together. how many clocks did anne buy?

Solution:

Let number of clocks does Anne possess when she and Jane leave shop

         = p clocks

Number of Clocks possessed by Jane when she and Anne left shop

           =  2 p clocks

Number of clocks bought by Jane while travelling from garage to home

        = 4 clocks

Total Clocks does Jane possess currently = 10

→→→Expressing the above statement in equation form

→2 p + 4 = 10

→ 2 p = 10 - 4  [Bringing variable on Right side of equation]

→2 p = 6

→p = 3     ⇒ [Dividing both side by 2]

Number of clocks bought by Anne when she was in garage = 3 clocks

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

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step-by-step explanation: