Suppose that circles r and s have a central angle measuring 80°. additionally, circle r has a radius of 3 ft and the radius of circle s is 6 ft. if the measure of the sector for circle r is 2π ft2, what is the area of the sector for circle s?

Let 

rA> radius of the circle R

rB> radius of the circle S

SA> the area of the sector for circle R

SB> the area of the sector for circle S

we have that

rA=3 ft

rB=6 ft

rA/rB=3/6> 1/2> rB/rA=2

SA=2π ft²

we know that

if Both circle A and circle B have a central angle , the square of the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the area of the sector for circle A to the area of the sector for circle B

(rA/rB) ^2=SA/SB> SB=SA*(rB/rA) ^2> SB=(2) ^2*(2π)--->

SB > 8π ft²

the answer is

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: