Find the equation for the line that passes through a's hypotenuse plz show work

The answer is:  " 1 " 

              " y = -2x + 1 " .

Explanation:


Look at the hypotenuse for "ΔA" and note the coordinates of where the hypotenuse crosses the "y-axis".

The coordinates are:  " (0, 1) " ;  that is:  " x = 0 ;  y = 1 " .

So, the problem /question is:  " y = -2x + [?] " ; 

→ Plug in " 1 " for "y" ;  as follows:

→  " 1 = -2x + [?] " ; 

→  We know that "x = 0";  

→ when "x = 0" ;    →  " -2x " = " (-2 * 0) = 0 ;  

So,  1 = 0 + [?] ; 

The answer is " 1 " ; since:  " { 0 + 1 = 1 .} .

Or, with a more detailed explanation:

  →  1  =  0  +  [?]  ;

Subtract "0" from EACH SIDE of the equation;
 
  →  1  − 0 =  0  +  [?]  − 0 ; 

to get:

 →  1 = [?] ; 

The answer is:  " 1 " .

The answer for you question is b