Alocal café serves tea, coffee, cookies, scones, and muffins. they recently gathered data about their customers who purchased both a drink and a snack. the given frequency table shows the results of the survey. if approximately 24% of the customers surveyed have a scone with their tea and approximately 36% of the customers surveyed buy a muffin, complete the column and row headings for the given table.

approximately 24% of the customers surveyed have a scone with their tea

From the table we can see that there is a total of 500 customers

24% of 500 = 0.24 * 500 = 120

So in the table  (row heading) above 120 we put Scone and to the left (column heading) we enter Tea

approximately 36% of the customers surveyed buy a muffin

36% of 500 = 0.36 * 500 = 180

So in the table , row heading above 120 is Muffin

So row heading is Scone, Muffin  and Cookie

Column heading is Coffee and Tea

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !