Ajar contains four blue marbles and two red marbles. suppose you choose a marble at random, and do not replace it. then you choose a second marble. find the probability of each event to the nearest tenth of a percent. a. the first marble is blue and the second is red b. both marbles are blue

a)

b)

Step-by-step explanation:

We are given the following information:

Number of red marbles in jar = 2

Number of blue marbles in jar = 4

Total number of marbles in jar = 6

Marbles are drawn from jar without replacement.

Formula:

a) Probability(First marble is blue and second is red)

=Probability(Drawing a blue marble in first draw) × Probability(Drawing a red marble in second draw)

b)  Probability(First marble is blue and second is also blue)

=Probability(Drawing a blue marble in first draw) × Probability(Drawing a blue marble in second draw)

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

they aren't great and cause destruction, idk man