Hey can you me posted picture of question

We have the following equation:
 3x2 + 7x + 4 = 0
 Using the resolver we have:
 x = (- b +/- root (b2 - 4ac)) / 2a
 Substituting values we have:
 x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
 Rewriting:
 x = (- 7 +/- root (49 - 48)) / 6
 x = (- 7 +/- root (1)) / 6
 x = (- 7 +/- 1) / 6
 The results are:
 x = (- 7 + 1) / 6 = -6/6 = -1
 x = (- 7 - 1) / 6 = -8 / 6 = -4/3
 
 x = -1
 x = -4/3
 option C and D

They are somewhat similar