Use the three steps to solve the problem. betty has 10 more dimes than quarters. if she has $3.45, how many coins does she have? { a0quarters, a1dimes }

betty has 24 coins.

Step-by-step explanation:

Let Betty has number of dimes ($0.10) = D

and number of quarters ($.25) = Q

Now equations will be

D = Q + 10 ----------(1)

(0.10)D + 0.25Q = 3.45 -----------(2)

Now by putting the value of D from equation (1) to equation (2)

.10Q + 1 + .25Q = 3.45

.35Q + 1 = 3.45

.35Q = 2.45

Q =

from equation (1)

D = 7 + 10 = 17

So betty has (7 + 17) = 24 coins.