Using a directrix of y = −2 and a focus of (1, 6), what quadratic function is created?

Answer with Step-by-step explanation:

The equation of the parabola with focus (a,b) and directrix y=c is:

(x−a)²+b²−c²=2(b−c)y

Here, directrix is y= -2 i.e. c= -2

focus=(1,6) i.e. (a,b)=(1,6)

Equation of parabola will be:

(x−1)²+6²−2²=2(6+2)y

(x−1)²+36-4=2×8y

(x−1)²+32=16y

(x−1)²=16y-32

(x−1)²=16(y-2)

Hence, equation of parabola is:

(x−1)²=16(y-2)

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

i need a picure

step-by-step explanation: