how many 2-inch by 3-inch by 8-inch bricks will you need to build a (uniformly wide) brick walk with the shape shown in the figure below? (lay the bricks so that the largest face is up. assume that a = 10 ft, b = 6 ft, and c = 22 ft.

Here we find the volume of the bricks, will be given by:
volume=length*width*height
v=2×3×8=48 in³

volume of the bricks is given by:
1 ft= 12 inches
thus our dimensions will be:
width=10*12=120 in
height=6*12=72 in
length=22*12=264 in
V=120×72×264
V=2,280,960 in³
Thus the number of bricks required will be:
2280960/48
=47520 in³