Find the mean median and interquartile range for the data set below 17,23,8,5,9,16,22,11,13,15,17,18

Mean = 14.5, Median = 15.5, IQR = 7.5

Step-by-step explanation:

Mean = Sum of data set / total number of data set

(17 + 23 + 8 + 5 + 9 + 16 +22 + 11 + 13 + 15 + 17 + 18)  ÷ 12

= 174 ÷ 12 = 14.5

Mean = 14.5

To get median first we arrange the data set in ascending order (from lowest to highest numbers

Therefore,

5, 8, 9, 11, 13, 15, 16, 17, 17, 18, 22 23  

The middle numbers are two, so we calculate the mean of these two numbers to get Median.

= (15+16)/2 = 31/2 = 15.5

Median = 15.5

Interquartile range is the difference of the first half and the second half of the data set. To calculate interquartile range (IQR), we find out the median of first half and the median of second half.

5, 8, 9, 11, 13, 15, 16, 17, 17, 18, 22 23  

Median of first half = (9+11)/2 = 20/2 = 10

Median of second half = (17+18)/2 = 35/2 =17.5

IQR = Median of second half - Median of first half

IQR = 17.5 - 10 = 7.5

Mean = 14.5, Median = 15.5, IQR = 7.5

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step-by-step explanation:

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d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.