Answers: 1
![z= \rho [\cos \theta + i \sin \theta]](/tpl/images/0121/2407/79e8c.png)
, can be calculated as follows:![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](/tpl/images/0121/2407/4d0e9.png)
is equal to![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](/tpl/images/0121/2407/513f5.png)
(1)
, (1) becomes![z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]](/tpl/images/0121/2407/95d8c.png)
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Do you know the correct answer?
Find [5(cos 330 degrees + i sin 330 degrees)]^3...
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