How do you find the vertex and axis of symmetry for this function, f(x)=3(x+1)^2

Answers:
Vertex is (-1,0)
Axis of symmetry is x = -1



Explanation:

F(x) = 3(x+1)^2
is the same as
y = 3(x-(-1))^2 + 0
which is in the form
y = a(x-h)^2 + k

We can see that
a = 3
h = -1
k = 0

Therefore the vertex is (h,k) = (-1,0)
The axis of symmetry is x = h = -1 which is the equation x = -1

The axis of symmetry in this case is a vertical line through the vertex. 

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3

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