What are the roots of the polynomial x^3-7x=6x-12

To solve the exercise shown above, you must follow the proccedure shown below:

 1. You have the following polynomial:

 x³-7x=6x-12

 2. When you factor it, you obtain the following expression:

 (x-3)(x-1)(x+4)=0

 3. Therefore, you have that the roots of the polynomial are:

 x1=-4
 x2=1
 x3=3