What is the vertex of the parabola? y+1=−14(x−2)2 enter your answer in the boxes?

Vertex ( h,k) : ( 2 ,-1) .

Step-by-step explanation:

Given : y+1=−14(x−2)².

To find : What is the vertex of the parabola?

Solution : We have given that  y+1=−14(x−2)².

Vertex form of parabola: y=a(x−h)²+k.

Where , ( h ,k ) are vertex

we have y+1=−14(x−2)²

On subtracting by both sides

y = −14(x−2)² - 1

On comparing with Vertex form of parabola

a = - 14 ;  h = 2 ; k = -1.

Therefore, Vertex ( h,k) : ( 2 ,-1) .

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

step-by-step explanation: