Public class test { public static void main(string[] args) { system. out. print("the grade is "); printgrade(78.5); system. out. print("the grade is "); printgrade(59.5); } public static printgrade(double score) { if (score > = 90.0) { system. out. println('a'); } else if (score > = 80.0) { system. out. println('b'); } else if (score > = 70.0) { system. out. println('c'); } else if (score > = 60.0) { system. out. println('d'); } else { system. out. println('f'); } } }

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.