David is standing 5000 feet away from the base of a cell phone tower. the angel of elevation from his eyes to the top of the tower is 78 degrees . if david’s eyes are 6 feet above the ground how y’all is the tower?

To solve this proble you must apply the proccedure shown below:

 1. You have that:

 - David is standing 5000 feet away from the base of a cell phone tower. and the angel of elevation from his eyes to the top of the tower is 78 degrees. 

 - David’s eyes are 6 feet.

 2. Therefore, you have:

 Tanα=opposite/adjacent
 Tanα=x/5000
 x=(5000)(Tan(78°))
 x=23,523.15 feet

 3. Then, you have that the height of the tower is:

 h=6 feet+23,523.15 feet
 h=23,529.15 feet

 The answer is:23,529.15 feet